1340330312020 has 96 divisors (see below), whose sum is σ = 3299908872960. Its totient is φ = 447699778560.

The previous prime is 1340330311981. The next prime is 1340330312023. The reversal of 1340330312020 is 202130330431.

It is a junction number, because it is equal to n+sod(n) for n = 1340330311982 and 1340330312000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340330312023) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3904987 + ... + 4234333.

It is an arithmetic number, because the mean of its divisors is an integer number (34374050760).

Almost surely, 2^{1340330312020} is an apocalyptic number.

1340330312020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1340330312020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1649954436480).

1340330312020 is an abundant number, since it is smaller than the sum of its proper divisors (1959578560940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340330312020 is a wasteful number, since it uses less digits than its factorization.

1340330312020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 330113 (or 330111 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 1340330312020 its reverse (202130330431), we get a palindrome (1542460642451).

The spelling of 1340330312020 in words is "one trillion, three hundred forty billion, three hundred thirty million, three hundred twelve thousand, twenty".