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1340331323120 = 245791307162263
BaseRepresentation
bin10011100000010001111…
…110001110111011110000
311202010121222211221121022
4103200101332032323300
5133424444304314440
62503423435515012
7165556442160656
oct23402176167360
94663558757538
101340331323120
114774820a9199
121979222b8a68
13995149c3a8a
1448c2db60dd6
1524ce9a56cb5
hex13811f8eef0

1340331323120 has 80 divisors (see below), whose sum is σ = 3158150722560. Its totient is φ = 528937773312.

The previous prime is 1340331323069. The next prime is 1340331323129. The reversal of 1340331323120 is 213231330431.

It is a tau number, because it is divible by the number of its divisors (80).

It is a self number, because there is not a number n which added to its sum of digits gives 1340331323120.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340331323129) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8179109 + ... + 8341371.

It is an arithmetic number, because the mean of its divisors is an integer number (39476884032).

Almost surely, 21340331323120 is an apocalyptic number.

1340331323120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1340331323120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1579075361280).

1340331323120 is an abundant number, since it is smaller than the sum of its proper divisors (1817819399440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340331323120 is a wasteful number, since it uses less digits than its factorization.

1340331323120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163662 (or 163656 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 1340331323120 its reverse (213231330431), we get a palindrome (1553562653551).

The spelling of 1340331323120 in words is "one trillion, three hundred forty billion, three hundred thirty-one million, three hundred twenty-three thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 40 79 80 158 316 395 632 790 1264 1307 1580 2614 3160 5228 6320 6535 10456 13070 20912 26140 52280 103253 104560 162263 206506 324526 413012 516265 649052 811315 826024 1032530 1298104 1622630 1652048 2065060 2596208 3245260 4130120 6490520 8260240 12818777 12981040 25637554 51275108 64093885 102550216 128187770 205100432 212077741 256375540 424155482 512751080 848310964 1025502160 1060388705 1696621928 2120777410 3393243856 4241554820 8483109640 16754141539 16966219280 33508283078 67016566156 83770707695 134033132312 167541415390 268066264624 335082830780 670165661560 1340331323120