Base | Representation |
---|---|
bin | 11110011110011100000101… |
… | …101101000110001101111100 |
3 | 122120120102221222200020002201 |
4 | 132132130011231012031330 |
5 | 120031444332332124200 |
6 | 1153021550255401244 |
7 | 40142401106063620 |
oct | 3636340555061574 |
9 | 576512858606081 |
10 | 134033140114300 |
11 | 397861543a3209 |
12 | 1304862b523224 |
13 | 59a336a1775bb |
14 | 251534a9c3180 |
15 | 1076799b9bc6a |
hex | 79e705b4637c |
134033140114300 has 72 divisors (see below), whose sum is σ = 340132470989696. Its totient is φ = 44885516679360.
The previous prime is 134033140114283. The next prime is 134033140114301. The reversal of 134033140114300 is 3411041330431.
It is a Harshad number since it is a multiple of its sum of digits (28).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134033140114301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2226434022 + ... + 2226494221.
Almost surely, 2134033140114300 is an apocalyptic number.
134033140114300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134033140114300 is an abundant number, since it is smaller than the sum of its proper divisors (206099330875396).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134033140114300 is a wasteful number, since it uses less digits than its factorization.
134033140114300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4452928307 (or 4452928300 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 134033140114300 its reverse (3411041330431), we get a palindrome (137444181444731).
The spelling of 134033140114300 in words is "one hundred thirty-four trillion, thirty-three billion, one hundred forty million, one hundred fourteen thousand, three hundred".
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