Base | Representation |
---|---|
bin | 10011100000010010101… |
… | …111001000000011110011 |
3 | 11202010122212222010002021 |
4 | 103200102233020003303 |
5 | 133430011044440034 |
6 | 2503425014332311 |
7 | 165556656132013 |
oct | 23402257100363 |
9 | 4663585863067 |
10 | 1340344140019 |
11 | 477489362775 |
12 | 19792665a097 |
13 | 99517560841 |
14 | 48c31739c43 |
15 | 24ceac396b4 |
hex | 13812bc80f3 |
1340344140019 has 2 divisors, whose sum is σ = 1340344140020. Its totient is φ = 1340344140018.
The previous prime is 1340344139987. The next prime is 1340344140043. The reversal of 1340344140019 is 9100414430431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1340344140019 - 25 = 1340344139987 is a prime.
It is a super-2 number, since 2×13403441400192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1340344140059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670172070009 + 670172070010.
It is an arithmetic number, because the mean of its divisors is an integer number (670172070010).
Almost surely, 21340344140019 is an apocalyptic number.
1340344140019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340344140019 is an equidigital number, since it uses as much as digits as its factorization.
1340344140019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 34.
The spelling of 1340344140019 in words is "one trillion, three hundred forty billion, three hundred forty-four million, one hundred forty thousand, nineteen".
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