Base | Representation |
---|---|
bin | 10011100000010010101… |
… | …111001000000100001011 |
3 | 11202010122212222010010011 |
4 | 103200102233020010023 |
5 | 133430011044440133 |
6 | 2503425014332351 |
7 | 165556656132046 |
oct | 23402257100413 |
9 | 4663585863104 |
10 | 1340344140043 |
11 | 477489362797 |
12 | 19792665a0b7 |
13 | 9951756085c |
14 | 48c31739c5d |
15 | 24ceac396cd |
hex | 13812bc810b |
1340344140043 has 2 divisors, whose sum is σ = 1340344140044. Its totient is φ = 1340344140042.
The previous prime is 1340344140019. The next prime is 1340344140059. The reversal of 1340344140043 is 3400414430431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1340344140043 - 29 = 1340344139531 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1340344139987 and 1340344140014.
It is not a weakly prime, because it can be changed into another prime (1340344140943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670172070021 + 670172070022.
It is an arithmetic number, because the mean of its divisors is an integer number (670172070022).
Almost surely, 21340344140043 is an apocalyptic number.
1340344140043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340344140043 is an equidigital number, since it uses as much as digits as its factorization.
1340344140043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1340344140043 its reverse (3400414430431), we get a palindrome (4740758570474).
The spelling of 1340344140043 in words is "one trillion, three hundred forty billion, three hundred forty-four million, one hundred forty thousand, forty-three".
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