Base | Representation |
---|---|
bin | 10011100000010010101… |
… | …111001000000011110111 |
3 | 11202010122212222010002102 |
4 | 103200102233020003313 |
5 | 133430011044440043 |
6 | 2503425014332315 |
7 | 165556656132020 |
oct | 23402257100367 |
9 | 4663585863072 |
10 | 1340344140023 |
11 | 477489362779 |
12 | 19792665a09b |
13 | 99517560845 |
14 | 48c31739c47 |
15 | 24ceac396b8 |
hex | 13812bc80f7 |
1340344140023 has 4 divisors (see below), whose sum is σ = 1531821874320. Its totient is φ = 1148866405728.
The previous prime is 1340344140019. The next prime is 1340344140043. The reversal of 1340344140023 is 3200414430431.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1340344140023 - 22 = 1340344140019 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340344140043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95738867138 + ... + 95738867151.
It is an arithmetic number, because the mean of its divisors is an integer number (382955468580).
Almost surely, 21340344140023 is an apocalyptic number.
1340344140023 is a deficient number, since it is larger than the sum of its proper divisors (191477734297).
1340344140023 is an equidigital number, since it uses as much as digits as its factorization.
1340344140023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 191477734296.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1340344140023 its reverse (3200414430431), we get a palindrome (4540758570454).
The spelling of 1340344140023 in words is "one trillion, three hundred forty billion, three hundred forty-four million, one hundred forty thousand, twenty-three".
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