Base | Representation |
---|---|
bin | 11110011110100000000110… |
… | …000100001011001100100111 |
3 | 122120120212001201210112020202 |
4 | 132132200012010023030213 |
5 | 120032032134412200203 |
6 | 1153023541141221115 |
7 | 40142612513114033 |
oct | 3636400604131447 |
9 | 576525051715222 |
10 | 134037441131303 |
11 | 39787a61195a16 |
12 | 1304942ba0179b |
13 | 59a38a4261988 |
14 | 2515637cd31c3 |
15 | 107694c582388 |
hex | 79e80610b327 |
134037441131303 has 2 divisors, whose sum is σ = 134037441131304. Its totient is φ = 134037441131302.
The previous prime is 134037441131287. The next prime is 134037441131309. The reversal of 134037441131303 is 303131144730431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134037441131303 - 24 = 134037441131287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134037441131309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67018720565651 + 67018720565652.
It is an arithmetic number, because the mean of its divisors is an integer number (67018720565652).
Almost surely, 2134037441131303 is an apocalyptic number.
134037441131303 is a deficient number, since it is larger than the sum of its proper divisors (1).
134037441131303 is an equidigital number, since it uses as much as digits as its factorization.
134037441131303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108864, while the sum is 38.
Adding to 134037441131303 its reverse (303131144730431), we get a palindrome (437168585861734).
The spelling of 134037441131303 in words is "one hundred thirty-four trillion, thirty-seven billion, four hundred forty-one million, one hundred thirty-one thousand, three hundred three".
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