Base | Representation |
---|---|
bin | 10011100000010100100… |
… | …111111001101011010001 |
3 | 11202010202002112122010202 |
4 | 103200110213321223101 |
5 | 133430042201104104 |
6 | 2503432105104545 |
7 | 165560522214503 |
oct | 23402447715321 |
9 | 4663662478122 |
10 | 1340375800529 |
11 | 4774a5217787 |
12 | 197935188155 |
13 | 99520c9757c |
14 | 48c35a1bd73 |
15 | 24ced8e051e |
hex | 138149f9ad1 |
1340375800529 has 2 divisors, whose sum is σ = 1340375800530. Its totient is φ = 1340375800528.
The previous prime is 1340375800469. The next prime is 1340375800531. The reversal of 1340375800529 is 9250085730431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1311592981504 + 28782819025 = 1145248^2 + 169655^2 .
It is a cyclic number.
It is not a de Polignac number, because 1340375800529 - 28 = 1340375800273 is a prime.
Together with 1340375800531, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1340375800549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670187900264 + 670187900265.
It is an arithmetic number, because the mean of its divisors is an integer number (670187900265).
Almost surely, 21340375800529 is an apocalyptic number.
It is an amenable number.
1340375800529 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340375800529 is an equidigital number, since it uses as much as digits as its factorization.
1340375800529 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 907200, while the sum is 47.
The spelling of 1340375800529 in words is "one trillion, three hundred forty billion, three hundred seventy-five million, eight hundred thousand, five hundred twenty-nine".
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