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1340401002324 = 223179624022813
BaseRepresentation
bin10011100000010110001…
…000000010011101010100
311202010210211222000111120
4103200112020002131110
5133430120124033244
62503434405203540
7165561246350226
oct23402610023524
94663724860446
101340401002324
1147750847020a
121979417005b0
139952627c587
1448c390dc416
1524d00c1c819
hex13816202754

1340401002324 has 24 divisors (see below), whose sum is σ = 3145074982560. Its totient is φ = 444304242144.

The previous prime is 1340401002307. The next prime is 1340401002331. The reversal of 1340401002324 is 4232001040431.

It is a junction number, because it is equal to n+sod(n) for n = 1340401002294 and 1340401002303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 312009259 + ... + 312013554.

It is an arithmetic number, because the mean of its divisors is an integer number (131044790940).

Almost surely, 21340401002324 is an apocalyptic number.

It is an amenable number.

1340401002324 is an abundant number, since it is smaller than the sum of its proper divisors (1804673980236).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340401002324 is a wasteful number, since it uses less digits than its factorization.

1340401002324 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 624022999 (or 624022997 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 1340401002324 its reverse (4232001040431), we get a palindrome (5572402042755).

The spelling of 1340401002324 in words is "one trillion, three hundred forty billion, four hundred one million, two thousand, three hundred twenty-four".

Divisors: 1 2 3 4 6 12 179 358 537 716 1074 2148 624022813 1248045626 1872068439 2496091252 3744136878 7488273756 111700083527 223400167054 335100250581 446800334108 670200501162 1340401002324