Base | Representation |
---|---|
bin | 1100001100001101110111… |
… | …0111111111001010001000 |
3 | 1202110102010020011121221110 |
4 | 3003003131313333022020 |
5 | 3224102413210423442 |
6 | 44301415540010320 |
7 | 2552260056362406 |
oct | 303033567771210 |
9 | 52412106147843 |
10 | 13404020404872 |
11 | 42a8682092849 |
12 | 16059573909a0 |
13 | 762cbc210946 |
14 | 344a88130476 |
15 | 183a08ed669c |
hex | c30dddff288 |
13404020404872 has 64 divisors (see below), whose sum is σ = 36172768752000. Its totient is φ = 4126375092224.
The previous prime is 13404020404811. The next prime is 13404020404883. The reversal of 13404020404872 is 27840402040431.
It is a super-3 number, since 3×134040204048723 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13404020404872.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 418650297 + ... + 418682312.
It is an arithmetic number, because the mean of its divisors is an integer number (565199511750).
Almost surely, 213404020404872 is an apocalyptic number.
13404020404872 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13404020404872 is an abundant number, since it is smaller than the sum of its proper divisors (22768748347128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13404020404872 is a wasteful number, since it uses less digits than its factorization.
13404020404872 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 837332670 (or 837332666 counting only the distinct ones).
The product of its (nonzero) digits is 172032, while the sum is 39.
The spelling of 13404020404872 in words is "thirteen trillion, four hundred four billion, twenty million, four hundred four thousand, eight hundred seventy-two".
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