Base | Representation |
---|---|
bin | 111110011010101111… |
… | …1100100101111101111 |
3 | 110210222120122110110112 |
4 | 1330311133210233233 |
5 | 4144004103034344 |
6 | 141324445330235 |
7 | 12453446400512 |
oct | 1746537445757 |
9 | 423876573415 |
10 | 134041455599 |
11 | 519349a8587 |
12 | 21b8a26697b |
13 | c84227c48c |
14 | 66b8130d79 |
15 | 3747a76c9e |
hex | 1f357e4bef |
134041455599 has 2 divisors, whose sum is σ = 134041455600. Its totient is φ = 134041455598.
The previous prime is 134041455539. The next prime is 134041455601. The reversal of 134041455599 is 995554140431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134041455599 - 28 = 134041455343 is a prime.
It is a super-2 number, since 2×1340414555992 (a number of 23 digits) contains 22 as substring.
Together with 134041455601, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134041455539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67020727799 + 67020727800.
It is an arithmetic number, because the mean of its divisors is an integer number (67020727800).
Almost surely, 2134041455599 is an apocalyptic number.
134041455599 is a deficient number, since it is larger than the sum of its proper divisors (1).
134041455599 is an equidigital number, since it uses as much as digits as its factorization.
134041455599 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944000, while the sum is 50.
The spelling of 134041455599 in words is "one hundred thirty-four billion, forty-one million, four hundred fifty-five thousand, five hundred ninety-nine".
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