1340426333 has 2 divisors, whose sum is σ = 1340426334. Its totient is φ = 1340426332.

The previous prime is 1340426327. The next prime is 1340426363. The reversal of 1340426333 is 3336240431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 690533284 + 649893049 = 26278^2 + 25493^2 .

It is an emirp because it is prime and its reverse (3336240431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340426333 - 2⁸ = 1340426077 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1340426296 and 1340426305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340426303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670213166 + 670213167.

It is an arithmetic number, because the mean of its divisors is an integer number (670213167).

Almost surely, 2^1340426333 is an apocalyptic number.

It is an amenable number.

1340426333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340426333 is an equidigital number, since it uses as much as digits as its factorization.

1340426333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 29.

The square root of 1340426333 is about 36611.8332373565. The cubic root of 1340426333 is about 1102.5906796866.

Adding to 1340426333 its reverse (3336240431), we get a palindrome (4676666764).

The spelling of 1340426333 in words is "one billion, three hundred forty million, four hundred twenty-six thousand, three hundred thirty-three".