Base | Representation |
---|---|
bin | 111110011010110011… |
… | …0110000111010001111 |
3 | 110210222201012012222010 |
4 | 1330311212300322033 |
5 | 4144010043343211 |
6 | 141324553552303 |
7 | 12453501410610 |
oct | 1746546607217 |
9 | 423881165863 |
10 | 134043340431 |
11 | 51935a756a0 |
12 | 21b8aa15693 |
13 | c84278c370 |
14 | 66b84a1c07 |
15 | 3747cea4a6 |
hex | 1f359b0e8f |
134043340431 has 32 divisors (see below), whose sum is σ = 239965705728. Its totient is φ = 64276525440.
The previous prime is 134043340421. The next prime is 134043340451.
134043340431 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 134043340431 - 211 = 134043338383 is a prime.
It is a super-2 number, since 2×1340433404312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134043340421) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22315236 + ... + 22321241.
It is an arithmetic number, because the mean of its divisors is an integer number (7498928304).
Almost surely, 2134043340431 is an apocalyptic number.
134043340431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
134043340431 is a deficient number, since it is larger than the sum of its proper divisors (105922365297).
134043340431 is a wasteful number, since it uses less digits than its factorization.
134043340431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44636511.
The product of its (nonzero) digits is 20736, while the sum is 30.
It can be divided in two parts, 134043 and 340431, that added together give a palindrome (474474).
The spelling of 134043340431 in words is "one hundred thirty-four billion, forty-three million, three hundred forty thousand, four hundred thirty-one".
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