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1340435203 is a prime number
BaseRepresentation
bin100111111100101…
…0110101100000011
310110102021011102021
41033321112230003
510221122411303
6341002102311
745134340232
oct11771265403
93412234367
101340435203
11628705898
12314aaa997
13184924933
14ca048b19
157ca2aebd
hex4fe56b03

1340435203 has 2 divisors, whose sum is σ = 1340435204. Its totient is φ = 1340435202.

The previous prime is 1340435197. The next prime is 1340435209. The reversal of 1340435203 is 3025340431.

It is a balanced prime because it is at equal distance from previous prime (1340435197) and next prime (1340435209).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340435203 is a prime.

It is a super-3 number, since 3×13404352033 (a number of 28 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1340435209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670217601 + 670217602.

It is an arithmetic number, because the mean of its divisors is an integer number (670217602).

Almost surely, 21340435203 is an apocalyptic number.

1340435203 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340435203 is an equidigital number, since it uses as much as digits as its factorization.

1340435203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 1340435203 is about 36611.9543728548. The cubic root of 1340435203 is about 1102.5931117381.

Adding to 1340435203 its reverse (3025340431), we get a palindrome (4365775634).

The spelling of 1340435203 in words is "one billion, three hundred forty million, four hundred thirty-five thousand, two hundred three".