Base | Representation |
---|---|
bin | 111110011010110100… |
… | …1010101001101100101 |
3 | 110210222202110102010101 |
4 | 1330311221111031211 |
5 | 4144010231412123 |
6 | 141325020224101 |
7 | 12453510212632 |
oct | 1746551251545 |
9 | 423882412111 |
10 | 134044013413 |
11 | 51936395282 |
12 | 21b8b09b031 |
13 | c84296678b |
14 | 66b85d9189 |
15 | 3747dceaad |
hex | 1f35a55365 |
134044013413 has 2 divisors, whose sum is σ = 134044013414. Its totient is φ = 134044013412.
The previous prime is 134044013407. The next prime is 134044013417. The reversal of 134044013413 is 314310440431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125685848484 + 8358164929 = 354522^2 + 91423^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134044013413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134044013417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67022006706 + 67022006707.
It is an arithmetic number, because the mean of its divisors is an integer number (67022006707).
Almost surely, 2134044013413 is an apocalyptic number.
It is an amenable number.
134044013413 is a deficient number, since it is larger than the sum of its proper divisors (1).
134044013413 is an equidigital number, since it uses as much as digits as its factorization.
134044013413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 134044013413 its reverse (314310440431), we get a palindrome (448354453844).
The spelling of 134044013413 in words is "one hundred thirty-four billion, forty-four million, thirteen thousand, four hundred thirteen".
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