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134044013413 is a prime number
BaseRepresentation
bin111110011010110100…
…1010101001101100101
3110210222202110102010101
41330311221111031211
54144010231412123
6141325020224101
712453510212632
oct1746551251545
9423882412111
10134044013413
1151936395282
1221b8b09b031
13c84296678b
1466b85d9189
153747dceaad
hex1f35a55365

134044013413 has 2 divisors, whose sum is σ = 134044013414. Its totient is φ = 134044013412.

The previous prime is 134044013407. The next prime is 134044013417. The reversal of 134044013413 is 314310440431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125685848484 + 8358164929 = 354522^2 + 91423^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134044013413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134044013417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67022006706 + 67022006707.

It is an arithmetic number, because the mean of its divisors is an integer number (67022006707).

Almost surely, 2134044013413 is an apocalyptic number.

It is an amenable number.

134044013413 is a deficient number, since it is larger than the sum of its proper divisors (1).

134044013413 is an equidigital number, since it uses as much as digits as its factorization.

134044013413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 134044013413 its reverse (314310440431), we get a palindrome (448354453844).

The spelling of 134044013413 in words is "one hundred thirty-four billion, forty-four million, thirteen thousand, four hundred thirteen".