13404436150117 has 2 divisors, whose sum is σ = 13404436150118. Its totient is φ = 13404436150116.

The previous prime is 13404436150093. The next prime is 13404436150141. The reversal of 13404436150117 is 71105163440431.

It is a balanced prime because it is at equal distance from previous prime (13404436150093) and next prime (13404436150141).

It can be written as a sum of positive squares in only one way, i.e., 9591941691396 + 3812494458721 = 3097086^2 + 1952561^2 .

It is a cyclic number.

It is not a de Polignac number, because 13404436150117 - 2³⁵ = 13370076411749 is a prime.

It is a super-2 number, since 2×13404436150117² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13404436150117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13404436159117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702218075058 + 6702218075059.

It is an arithmetic number, because the mean of its divisors is an integer number (6702218075059).

Almost surely, 2^{13404436150117} is an apocalyptic number.

It is an amenable number.

13404436150117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13404436150117 is an equidigital number, since it uses as much as digits as its factorization.

13404436150117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 40.

Adding to 13404436150117 its reverse (71105163440431), we get a palindrome (84509599590548).

The spelling of 13404436150117 in words is "thirteen trillion, four hundred four billion, four hundred thirty-six million, one hundred fifty thousand, one hundred seventeen".