134045334352140 has 24 divisors (see below), whose sum is σ = 375326936186160. Its totient is φ = 35745422493888.

The previous prime is 134045334352123. The next prime is 134045334352159. The reversal of 134045334352140 is 41253433540431.

134045334352140 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×134045334352140³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134045334352092 and 134045334352101.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1117044452875 + ... + 1117044452994.

It is an arithmetic number, because the mean of its divisors is an integer number (15638622341090).

Almost surely, 2^{134045334352140} is an apocalyptic number.

134045334352140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134045334352140 is an abundant number, since it is smaller than the sum of its proper divisors (241281601834020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134045334352140 is a wasteful number, since it uses less digits than its factorization.

134045334352140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2234088905881 (or 2234088905879 counting only the distinct ones).

The product of its (nonzero) digits is 1036800, while the sum is 42.

Adding to 134045334352140 its reverse (41253433540431), we get a palindrome (175298767892571).

The spelling of 134045334352140 in words is "one hundred thirty-four trillion, forty-five billion, three hundred thirty-four million, three hundred fifty-two thousand, one hundred forty".