Base | Representation |
---|---|
bin | 1111111110101… |
… | …10010111111111 |
3 | 100100020022020021 |
4 | 13333112113333 |
5 | 233304002411 |
6 | 21145033011 |
7 | 3215245153 |
oct | 777262777 |
9 | 310208207 |
10 | 134047231 |
11 | 6973673a |
12 | 38a85767 |
13 | 21a049b6 |
14 | 13b35063 |
15 | bb7ca71 |
hex | 7fd65ff |
134047231 has 2 divisors, whose sum is σ = 134047232. Its totient is φ = 134047230.
The previous prime is 134047217. The next prime is 134047253. The reversal of 134047231 is 132740431.
134047231 is nontrivially palindromic in base 8.
It is a weak prime.
It is an emirp because it is prime and its reverse (132740431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134047231 - 29 = 134046719 is a prime.
It is a super-2 number, since 2×1340472312 = 35937320277534722, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134047196 and 134047205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134047031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67023615 + 67023616.
It is an arithmetic number, because the mean of its divisors is an integer number (67023616).
Almost surely, 2134047231 is an apocalyptic number.
134047231 is a deficient number, since it is larger than the sum of its proper divisors (1).
134047231 is an equidigital number, since it uses as much as digits as its factorization.
134047231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
The square root of 134047231 is about 11577.8767915365. The cubic root of 134047231 is about 511.7831099889.
Adding to 134047231 its reverse (132740431), we get a palindrome (266787662).
The spelling of 134047231 in words is "one hundred thirty-four million, forty-seven thousand, two hundred thirty-one".
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