Base | Representation |
---|---|
bin | 10011100000011010011… |
… | …111111011001000001111 |
3 | 11202010222222000121122001 |
4 | 103200122133323020033 |
5 | 133430242414410443 |
6 | 2503445545533131 |
7 | 165563130111631 |
oct | 23403237731017 |
9 | 4663888017561 |
10 | 1340474372623 |
11 | 477545923421 |
12 | 1979621a41a7 |
13 | 9953852b159 |
14 | 48c44b5aa51 |
15 | 24d073b1d4d |
hex | 1381a7fb20f |
1340474372623 has 2 divisors, whose sum is σ = 1340474372624. Its totient is φ = 1340474372622.
The previous prime is 1340474372621. The next prime is 1340474372683. The reversal of 1340474372623 is 3262734740431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340474372623 - 21 = 1340474372621 is a prime.
Together with 1340474372621, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340474372621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670237186311 + 670237186312.
It is an arithmetic number, because the mean of its divisors is an integer number (670237186312).
Almost surely, 21340474372623 is an apocalyptic number.
1340474372623 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340474372623 is an equidigital number, since it uses as much as digits as its factorization.
1340474372623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2032128, while the sum is 46.
The spelling of 1340474372623 in words is "one trillion, three hundred forty billion, four hundred seventy-four million, three hundred seventy-two thousand, six hundred twenty-three".
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