1340474373653 has 2 divisors, whose sum is σ = 1340474373654. Its totient is φ = 1340474373652.

The previous prime is 1340474373647. The next prime is 1340474373659. The reversal of 1340474373653 is 3563734740431.

It is a balanced prime because it is at equal distance from previous prime (1340474373647) and next prime (1340474373659).

It can be written as a sum of positive squares in only one way, i.e., 686417221009 + 654057152644 = 828503^2 + 808738^2 .

It is an emirp because it is prime and its reverse (3563734740431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340474373653 - 2¹² = 1340474369557 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340474373659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670237186826 + 670237186827.

It is an arithmetic number, because the mean of its divisors is an integer number (670237186827).

Almost surely, 2^{1340474373653} is an apocalyptic number.

It is an amenable number.

1340474373653 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340474373653 is an equidigital number, since it uses as much as digits as its factorization.

1340474373653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7620480, while the sum is 50.

The spelling of 1340474373653 in words is "one trillion, three hundred forty billion, four hundred seventy-four million, three hundred seventy-three thousand, six hundred fifty-three".