1340477471381 has 2 divisors, whose sum is σ = 1340477471382. Its totient is φ = 1340477471380.

The previous prime is 1340477471357. The next prime is 1340477471471. The reversal of 1340477471381 is 1831747740431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 947768449156 + 392709022225 = 973534^2 + 626665^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340477471381 - 2⁶ = 1340477471317 is a prime.

It is a super-2 number, since 2×1340477471381² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340477471341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670238735690 + 670238735691.

It is an arithmetic number, because the mean of its divisors is an integer number (670238735691).

Almost surely, 2^{1340477471381} is an apocalyptic number.

It is an amenable number.

1340477471381 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340477471381 is an equidigital number, since it uses as much as digits as its factorization.

1340477471381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1580544, while the sum is 50.

The spelling of 1340477471381 in words is "one trillion, three hundred forty billion, four hundred seventy-seven million, four hundred seventy-one thousand, three hundred eighty-one".