Base | Representation |
---|---|
bin | 10011100000011010101… |
… | …011101111101011001110 |
3 | 11202011000011212001101222 |
4 | 103200122223233223032 |
5 | 133430244213041223 |
6 | 2503450140203342 |
7 | 165563165336240 |
oct | 23403253575316 |
9 | 4664004761358 |
10 | 1340477471438 |
11 | 47754764a626 |
12 | 197963239552 |
13 | 99539074781 |
14 | 48c45326090 |
15 | 24d077c50c8 |
hex | 1381aaeface |
1340477471438 has 8 divisors (see below), whose sum is σ = 2297961379632. Its totient is φ = 574490344896.
The previous prime is 1340477471381. The next prime is 1340477471471. The reversal of 1340477471438 is 8341747740431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1340477471438.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47874195395 + ... + 47874195422.
It is an arithmetic number, because the mean of its divisors is an integer number (287245172454).
Almost surely, 21340477471438 is an apocalyptic number.
1340477471438 is a deficient number, since it is larger than the sum of its proper divisors (957483908194).
1340477471438 is an equidigital number, since it uses as much as digits as its factorization.
1340477471438 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95748390826.
The product of its (nonzero) digits is 6322176, while the sum is 53.
The spelling of 1340477471438 in words is "one trillion, three hundred forty billion, four hundred seventy-seven million, four hundred seventy-one thousand, four hundred thirty-eight".
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