Base | Representation |
---|---|
bin | 10011100000011100011… |
… | …000110000111101111111 |
3 | 11202011002011122000102012 |
4 | 103200130120300331333 |
5 | 133430324022103211 |
6 | 2503453040521435 |
7 | 165563663266022 |
oct | 23403430607577 |
9 | 4664064560365 |
10 | 1340506050431 |
11 | 47756179a429 |
12 | 19797092027b |
13 | 99541c6ca12 |
14 | 48c490451b9 |
15 | 24d0a06cd8b |
hex | 1381c630f7f |
1340506050431 has 2 divisors, whose sum is σ = 1340506050432. Its totient is φ = 1340506050430.
The previous prime is 1340506050421. The next prime is 1340506050467.
1340506050431 is nontrivially palindromic in base 10.
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 1340506050431 - 230 = 1339432308607 is a prime.
It is a super-2 number, since 2×13405060504312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340506050421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670253025215 + 670253025216.
It is an arithmetic number, because the mean of its divisors is an integer number (670253025216).
Almost surely, 21340506050431 is an apocalyptic number.
1340506050431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340506050431 is an equidigital number, since it uses as much as digits as its factorization.
1340506050431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
The spelling of 1340506050431 in words is "one trillion, three hundred forty billion, five hundred six million, fifty thousand, four hundred thirty-one".
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