Base | Representation |
---|---|
bin | 11000111110000001… |
… | …10101100111010111 |
3 | 1021121020021111012112 |
4 | 30133000311213113 |
5 | 204423213341231 |
6 | 10054104141235 |
7 | 653123310014 |
oct | 143700654727 |
9 | 37536244175 |
10 | 13405215191 |
11 | 5759992645 |
12 | 272146781b |
13 | 135831acc4 |
14 | 9124ca70b |
15 | 536ce592b |
hex | 31f0359d7 |
13405215191 has 2 divisors, whose sum is σ = 13405215192. Its totient is φ = 13405215190.
The previous prime is 13405215133. The next prime is 13405215221. The reversal of 13405215191 is 19151250431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13405215191 - 210 = 13405214167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13405215091) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702607595 + 6702607596.
It is an arithmetic number, because the mean of its divisors is an integer number (6702607596).
Almost surely, 213405215191 is an apocalyptic number.
13405215191 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405215191 is an equidigital number, since it uses as much as digits as its factorization.
13405215191 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 32.
The spelling of 13405215191 in words is "thirteen billion, four hundred five million, two hundred fifteen thousand, one hundred ninety-one".
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