Base | Representation |
---|---|
bin | 11000111110000001… |
… | …10101100111110111 |
3 | 1021121020021111020201 |
4 | 30133000311213313 |
5 | 204423213341343 |
6 | 10054104141331 |
7 | 653123310061 |
oct | 143700654767 |
9 | 37536244221 |
10 | 13405215223 |
11 | 5759992674 |
12 | 2721467847 |
13 | 135831b01a |
14 | 9124ca731 |
15 | 536ce594d |
hex | 31f0359f7 |
13405215223 has 8 divisors (see below), whose sum is σ = 13423536000. Its totient is φ = 13386910008.
The previous prime is 13405215221. The next prime is 13405215233. The reversal of 13405215223 is 32251250431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13405215223 - 21 = 13405215221 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13405215191 and 13405215200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405215221) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3236688 + ... + 3240826.
It is an arithmetic number, because the mean of its divisors is an integer number (1677942000).
Almost surely, 213405215223 is an apocalyptic number.
13405215223 is a deficient number, since it is larger than the sum of its proper divisors (18320777).
13405215223 is a wasteful number, since it uses less digits than its factorization.
13405215223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7781.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 13405215223 its reverse (32251250431), we get a palindrome (45656465654).
The spelling of 13405215223 in words is "thirteen billion, four hundred five million, two hundred fifteen thousand, two hundred twenty-three".
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