Base | Representation |
---|---|
bin | 1100001100010011000110… |
… | …1000110011111101101000 |
3 | 1202110112202011111200021122 |
4 | 3003010301220303331220 |
5 | 3224113302440304000 |
6 | 44302211220354412 |
7 | 2552336642323556 |
oct | 303046150637550 |
9 | 52415664450248 |
10 | 13405425713000 |
11 | 42a9233377622 |
12 | 1606089b45a08 |
13 | 7631843ca509 |
14 | 344b7ca24bd6 |
15 | 183a8c579085 |
hex | c3131a33f68 |
13405425713000 has 64 divisors (see below), whose sum is σ = 31656482629200. Its totient is φ = 5312976019200.
The previous prime is 13405425712981. The next prime is 13405425713033. The reversal of 13405425713000 is 31752450431.
It can be written as a sum of positive squares in 8 ways, for example, as 1338986865316 + 12066438847684 = 1157146^2 + 3473678^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61383779 + ... + 61601778.
Almost surely, 213405425713000 is an apocalyptic number.
13405425713000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13405425713000 is an abundant number, since it is smaller than the sum of its proper divisors (18251056916200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13405425713000 is a wasteful number, since it uses less digits than its factorization.
13405425713000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 122985687 (or 122985673 counting only the distinct ones).
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 13405425713000 in words is "thirteen trillion, four hundred five billion, four hundred twenty-five million, seven hundred thirteen thousand".
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