Base | Representation |
---|---|
bin | 111110011011011111… |
… | …1110010111001111011 |
3 | 110211001100002222001002 |
4 | 1330312333302321323 |
5 | 4144032032220134 |
6 | 141331150115215 |
7 | 12454203654401 |
oct | 1746677627173 |
9 | 424040088032 |
10 | 134066679419 |
11 | 51948166612 |
12 | 21b967abb0b |
13 | c84757150a |
14 | 66bb619471 |
15 | 3749daa87e |
hex | 1f36ff2e7b |
134066679419 has 2 divisors, whose sum is σ = 134066679420. Its totient is φ = 134066679418.
The previous prime is 134066679401. The next prime is 134066679421. The reversal of 134066679419 is 914976660431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134066679419 - 232 = 129771712123 is a prime.
It is a super-2 number, since 2×1340666794192 (a number of 23 digits) contains 22 as substring.
Together with 134066679421, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (134066679619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67033339709 + 67033339710.
It is an arithmetic number, because the mean of its divisors is an integer number (67033339710).
Almost surely, 2134066679419 is an apocalyptic number.
134066679419 is a deficient number, since it is larger than the sum of its proper divisors (1).
134066679419 is an equidigital number, since it uses as much as digits as its factorization.
134066679419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5878656, while the sum is 56.
The spelling of 134066679419 in words is "one hundred thirty-four billion, sixty-six million, six hundred seventy-nine thousand, four hundred nineteen".
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