13406671141 has 2 divisors, whose sum is σ = 13406671142. Its totient is φ = 13406671140.

The previous prime is 13406671099. The next prime is 13406671163. The reversal of 13406671141 is 14117660431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10338619041 + 3068052100 = 101679^2 + 55390^2 .

It is a cyclic number.

It is not a de Polignac number, because 13406671141 - 2²⁵ = 13373116709 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13406671097 and 13406671106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13406671171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703335570 + 6703335571.

It is an arithmetic number, because the mean of its divisors is an integer number (6703335571).

Almost surely, 2^13406671141 is an apocalyptic number.

It is an amenable number.

13406671141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13406671141 is an equidigital number, since it uses as much as digits as its factorization.

13406671141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 34.

The spelling of 13406671141 in words is "thirteen billion, four hundred six million, six hundred seventy-one thousand, one hundred forty-one".