Base | Representation |
---|---|
bin | 11000111110001101… |
… | …11011110101100111 |
3 | 1021121100021200201202 |
4 | 30133012323311213 |
5 | 204424121013133 |
6 | 10054202313115 |
7 | 653143014644 |
oct | 143706736547 |
9 | 37540250652 |
10 | 13406813543 |
11 | 575a8844a2 |
12 | 2721ab879b |
13 | 135875a686 |
14 | 9127c4dcb |
15 | 53700e2e8 |
hex | 31f1bbd67 |
13406813543 has 2 divisors, whose sum is σ = 13406813544. Its totient is φ = 13406813542.
The previous prime is 13406813389. The next prime is 13406813587. The reversal of 13406813543 is 34531860431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13406813543 - 212 = 13406809447 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13406813497 and 13406813506.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13406813143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703406771 + 6703406772.
It is an arithmetic number, because the mean of its divisors is an integer number (6703406772).
Almost surely, 213406813543 is an apocalyptic number.
13406813543 is a deficient number, since it is larger than the sum of its proper divisors (1).
13406813543 is an equidigital number, since it uses as much as digits as its factorization.
13406813543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 38.
The spelling of 13406813543 in words is "thirteen billion, four hundred six million, eight hundred thirteen thousand, five hundred forty-three".
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