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1340800801481 is a prime number
BaseRepresentation
bin10011100000101101111…
…101001001101011001001
311202011211201020220211202
4103200231331021223021
5133431430001121411
62503542210233545
7165604202524361
oct23405575115311
94664751226752
101340800801481
114776a3109239
12197a335858b5
139958b05061b
1448c7624d9a1
1524d25d9183b
hex1382df49ac9

1340800801481 has 2 divisors, whose sum is σ = 1340800801482. Its totient is φ = 1340800801480.

The previous prime is 1340800801471. The next prime is 1340800801507. The reversal of 1340800801481 is 1841080080431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 940674973456 + 400125828025 = 969884^2 + 632555^2 .

It is an emirp because it is prime and its reverse (1841080080431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340800801481 is a prime.

It is a super-2 number, since 2×13408008014812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1340800801421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670400400740 + 670400400741.

It is an arithmetic number, because the mean of its divisors is an integer number (670400400741).

Almost surely, 21340800801481 is an apocalyptic number.

It is an amenable number.

1340800801481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340800801481 is an equidigital number, since it uses as much as digits as its factorization.

1340800801481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24576, while the sum is 38.

The spelling of 1340800801481 in words is "one trillion, three hundred forty billion, eight hundred million, eight hundred one thousand, four hundred eighty-one".