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13410151031 is a prime number
BaseRepresentation
bin11000111110100111…
…01010101001110111
31021121120120020220102
430133103222221313
5204430444313111
610054402024315
7653213255144
oct143723525167
937546506812
1013410151031
115761753a52
12272304809b
131359358814
149130133cb
1553746d13b
hex31f4eaa77

13410151031 has 2 divisors, whose sum is σ = 13410151032. Its totient is φ = 13410151030.

The previous prime is 13410151019. The next prime is 13410151033. The reversal of 13410151031 is 13015101431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13410151031 - 210 = 13410150007 is a prime.

It is a super-2 number, since 2×134101510312 (a number of 21 digits) contains 22 as substring.

Together with 13410151033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13410150994 and 13410151012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13410151033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705075515 + 6705075516.

It is an arithmetic number, because the mean of its divisors is an integer number (6705075516).

Almost surely, 213410151031 is an apocalyptic number.

13410151031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410151031 is an equidigital number, since it uses as much as digits as its factorization.

13410151031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 13410151031 its reverse (13015101431), we get a palindrome (26425252462).

The spelling of 13410151031 in words is "thirteen billion, four hundred ten million, one hundred fifty-one thousand, thirty-one".