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134103005815997 is a prime number
BaseRepresentation
bin11110011111011101001010…
…000001100110010010111101
3122120211010022001022121100002
4132133131022001212102331
5120034120423442102442
61153114023112044045
740150423332541211
oct3637351201462275
9576733261277302
10134103005815997
11398028467a7a49
121305a089393625
1359a9b2282cbaa
14251889783a941
1510784d85d0732
hex79f74a0664bd

134103005815997 has 2 divisors, whose sum is σ = 134103005815998. Its totient is φ = 134103005815996.

The previous prime is 134103005815967. The next prime is 134103005816011. The reversal of 134103005815997 is 799518500301431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86640744226201 + 47462261589796 = 9308101^2 + 6889286^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134103005815997 is a prime.

It is a super-3 number, since 3×1341030058159973 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134103005815967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67051502907998 + 67051502907999.

It is an arithmetic number, because the mean of its divisors is an integer number (67051502907999).

Almost surely, 2134103005815997 is an apocalyptic number.

It is an amenable number.

134103005815997 is a deficient number, since it is larger than the sum of its proper divisors (1).

134103005815997 is an equidigital number, since it uses as much as digits as its factorization.

134103005815997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4082400, while the sum is 56.

The spelling of 134103005815997 in words is "one hundred thirty-four trillion, one hundred three billion, five million, eight hundred fifteen thousand, nine hundred ninety-seven".