13410425140243 has 2 divisors, whose sum is σ = 13410425140244. Its totient is φ = 13410425140242.

The previous prime is 13410425140241. The next prime is 13410425140247. The reversal of 13410425140243 is 34204152401431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13410425140243 - 2¹ = 13410425140241 is a prime.

It is a super-2 number, since 2×13410425140243² (a number of 27 digits) contains 22 as substring.

Together with 13410425140241, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13410425140199 and 13410425140208.

It is not a weakly prime, because it can be changed into another prime (13410425140241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705212570121 + 6705212570122.

It is an arithmetic number, because the mean of its divisors is an integer number (6705212570122).

Almost surely, 2^{13410425140243} is an apocalyptic number.

13410425140243 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410425140243 is an equidigital number, since it uses as much as digits as its factorization.

13410425140243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 13410425140243 its reverse (34204152401431), we get a palindrome (47614577541674).

The spelling of 13410425140243 in words is "thirteen trillion, four hundred ten billion, four hundred twenty-five million, one hundred forty thousand, two hundred forty-three".