Base | Representation |
---|---|
bin | 111110011100110101… |
… | …0011001010110000111 |
3 | 110211011110021001222221 |
4 | 1330321222121112013 |
5 | 4144130004320401 |
6 | 141335424433211 |
7 | 12455256050134 |
oct | 1747152312607 |
9 | 424143231887 |
10 | 134111401351 |
11 | 51970431894 |
12 | 21ba9778807 |
13 | c8538cc3b5 |
14 | 66c353b58b |
15 | 374dc917a1 |
hex | 1f39a99587 |
134111401351 has 2 divisors, whose sum is σ = 134111401352. Its totient is φ = 134111401350.
The previous prime is 134111401313. The next prime is 134111401373. The reversal of 134111401351 is 153104111431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134111401351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134111401451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67055700675 + 67055700676.
It is an arithmetic number, because the mean of its divisors is an integer number (67055700676).
Almost surely, 2134111401351 is an apocalyptic number.
134111401351 is a deficient number, since it is larger than the sum of its proper divisors (1).
134111401351 is an equidigital number, since it uses as much as digits as its factorization.
134111401351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 134111401351 its reverse (153104111431), we get a palindrome (287215512782).
The spelling of 134111401351 in words is "one hundred thirty-four billion, one hundred eleven million, four hundred one thousand, three hundred fifty-one".
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