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134112047 is a prime number
BaseRepresentation
bin1111111111001…
…10001100101111
3100100100121010212
413333212030233
5233313041142
621150253035
73215635136
oct777461457
9310317125
10134112047
1169780403
1238ab717b
1321a28354
1413b5091d
15bb91d82
hex7fe632f

134112047 has 2 divisors, whose sum is σ = 134112048. Its totient is φ = 134112046.

The previous prime is 134112001. The next prime is 134112071. The reversal of 134112047 is 740211431.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (740211431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134112047 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134112647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67056023 + 67056024.

It is an arithmetic number, because the mean of its divisors is an integer number (67056024).

Almost surely, 2134112047 is an apocalyptic number.

134112047 is a deficient number, since it is larger than the sum of its proper divisors (1).

134112047 is an equidigital number, since it uses as much as digits as its factorization.

134112047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672, while the sum is 23.

The square root of 134112047 is about 11580.6755847835. The cubic root of 134112047 is about 511.8655843743.

Adding to 134112047 its reverse (740211431), we get a palindrome (874323478).

The spelling of 134112047 in words is "one hundred thirty-four million, one hundred twelve thousand, forty-seven".