Base | Representation |
---|---|
bin | 11110011111100110011110… |
… | …011000011110011110100101 |
3 | 122120212002010022220100020121 |
4 | 132133212132120132132211 |
5 | 120034301421311042041 |
6 | 1153122400002401541 |
7 | 40151226302515105 |
oct | 3637463630363645 |
9 | 576762108810217 |
10 | 134113011034021 |
11 | 39807010456378 |
12 | 130600000602b1 |
13 | 59aaa58626446 |
14 | 251916655b205 |
15 | 10788c1b6e7d1 |
hex | 79f99e61e7a5 |
134113011034021 has 2 divisors, whose sum is σ = 134113011034022. Its totient is φ = 134113011034020.
The previous prime is 134113011033941. The next prime is 134113011034063. The reversal of 134113011034021 is 120430110311431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104789822156100 + 29323188877921 = 10236690^2 + 5415089^2 .
It is an emirp because it is prime and its reverse (120430110311431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134113011034021 is a prime.
It is a super-2 number, since 2×1341130110340212 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134113011034421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67056505517010 + 67056505517011.
It is an arithmetic number, because the mean of its divisors is an integer number (67056505517011).
Almost surely, 2134113011034021 is an apocalyptic number.
It is an amenable number.
134113011034021 is a deficient number, since it is larger than the sum of its proper divisors (1).
134113011034021 is an equidigital number, since it uses as much as digits as its factorization.
134113011034021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 134113011034021 its reverse (120430110311431), we get a palindrome (254543121345452).
The spelling of 134113011034021 in words is "one hundred thirty-four trillion, one hundred thirteen billion, eleven million, thirty-four thousand, twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •