Base | Representation |
---|---|
bin | 10011100001000001110… |
… | …000100011010110101001 |
3 | 11202012200212102112200101 |
4 | 103201001300203112221 |
5 | 133433120024334423 |
6 | 2504035155305401 |
7 | 165615345530023 |
oct | 23410160432651 |
9 | 4665625375611 |
10 | 1341133043113 |
11 | 4778537042a6 |
12 | 197b068ab261 |
13 | 99611b297c6 |
14 | 48ca8417013 |
15 | 24d4511d7ad |
hex | 13841c235a9 |
1341133043113 has 2 divisors, whose sum is σ = 1341133043114. Its totient is φ = 1341133043112.
The previous prime is 1341133043083. The next prime is 1341133043197. The reversal of 1341133043113 is 3113403311431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 923813167104 + 417319876009 = 961152^2 + 646003^2 .
It is a cyclic number.
It is not a de Polignac number, because 1341133043113 - 225 = 1341099488681 is a prime.
It is not a weakly prime, because it can be changed into another prime (1341133043413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670566521556 + 670566521557.
It is an arithmetic number, because the mean of its divisors is an integer number (670566521557).
Almost surely, 21341133043113 is an apocalyptic number.
It is an amenable number.
1341133043113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341133043113 is an equidigital number, since it uses as much as digits as its factorization.
1341133043113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 1341133043113 its reverse (3113403311431), we get a palindrome (4454536354544).
The spelling of 1341133043113 in words is "one trillion, three hundred forty-one billion, one hundred thirty-three million, forty-three thousand, one hundred thirteen".
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