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1341133043197 is a prime number
BaseRepresentation
bin10011100001000001110…
…000100011010111111101
311202012200212102112210111
4103201001300203113331
5133433120024340242
62504035155310021
7165615345530203
oct23410160432775
94665625375714
101341133043197
11477853704372
12197b068ab311
1399611b2985c
1448ca8417073
1524d4511d817
hex13841c235fd

1341133043197 has 2 divisors, whose sum is σ = 1341133043198. Its totient is φ = 1341133043196.

The previous prime is 1341133043113. The next prime is 1341133043207. The reversal of 1341133043197 is 7913403311431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1292448385881 + 48684657316 = 1136859^2 + 220646^2 .

It is an emirp because it is prime and its reverse (7913403311431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1341133043197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1341133043297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670566521598 + 670566521599.

It is an arithmetic number, because the mean of its divisors is an integer number (670566521599).

Almost surely, 21341133043197 is an apocalyptic number.

It is an amenable number.

1341133043197 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341133043197 is an equidigital number, since it uses as much as digits as its factorization.

1341133043197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 40.

The spelling of 1341133043197 in words is "one trillion, three hundred forty-one billion, one hundred thirty-three million, forty-three thousand, one hundred ninety-seven".