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134114244101 is a prime number
BaseRepresentation
bin111110011100111010…
…1001111011000000101
3110211011122121111111222
41330321311033120011
54144131221302401
6141340005410125
712455322160055
oct1747165173005
9424148544458
10134114244101
1151971aa3672
1221baa709945
13c8543862b6
1466c3a7b565
15374e153c1b
hex1f39d4f605

134114244101 has 2 divisors, whose sum is σ = 134114244102. Its totient is φ = 134114244100.

The previous prime is 134114244097. The next prime is 134114244133. The reversal of 134114244101 is 101442411431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95080339201 + 39033904900 = 308351^2 + 197570^2 .

It is an emirp because it is prime and its reverse (101442411431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134114244101 - 22 = 134114244097 is a prime.

It is a super-2 number, since 2×1341142441012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134114244701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67057122050 + 67057122051.

It is an arithmetic number, because the mean of its divisors is an integer number (67057122051).

Almost surely, 2134114244101 is an apocalyptic number.

It is an amenable number.

134114244101 is a deficient number, since it is larger than the sum of its proper divisors (1).

134114244101 is an equidigital number, since it uses as much as digits as its factorization.

134114244101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 134114244101 its reverse (101442411431), we get a palindrome (235556655532).

The spelling of 134114244101 in words is "one hundred thirty-four billion, one hundred fourteen million, two hundred forty-four thousand, one hundred one".