Base | Representation |
---|---|
bin | 1100001100101001110101… |
… | …1111011001000111011111 |
3 | 1202111010111121002020002111 |
4 | 3003022131133121013133 |
5 | 3224213303204302432 |
6 | 44305101043534451 |
7 | 2552644135225216 |
oct | 303123537310737 |
9 | 52433447066074 |
10 | 13411530150367 |
11 | 430088614a788 |
12 | 16072b238a427 |
13 | 76391800172b |
14 | 34519b65c07d |
15 | 183ce8441347 |
hex | c329d7d91df |
13411530150367 has 2 divisors, whose sum is σ = 13411530150368. Its totient is φ = 13411530150366.
The previous prime is 13411530150313. The next prime is 13411530150433. The reversal of 13411530150367 is 76305103511431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13411530150367 - 239 = 12861774336479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411530150467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705765075183 + 6705765075184.
It is an arithmetic number, because the mean of its divisors is an integer number (6705765075184).
Almost surely, 213411530150367 is an apocalyptic number.
13411530150367 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411530150367 is an equidigital number, since it uses as much as digits as its factorization.
13411530150367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 40.
Adding to 13411530150367 its reverse (76305103511431), we get a palindrome (89716633661798).
The spelling of 13411530150367 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty million, one hundred fifty thousand, three hundred sixty-seven".
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