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13411530150433 is a prime number
BaseRepresentation
bin1100001100101001110101…
…1111011001001000100001
31202111010111121002020011221
43003022131133121020201
53224213303204303213
644305101043535041
72552644135225342
oct303123537311041
952433447066157
1013411530150433
11430088614a838
1216072b238a481
1376391800177c
1434519b65c0c9
15183ce844138d
hexc329d7d9221

13411530150433 has 2 divisors, whose sum is σ = 13411530150434. Its totient is φ = 13411530150432.

The previous prime is 13411530150367. The next prime is 13411530150451. The reversal of 13411530150433 is 33405103511431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8243691819489 + 5167838330944 = 2871183^2 + 2273288^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411530150433 - 29 = 13411530149921 is a prime.

It is a super-2 number, since 2×134115301504332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13411530150833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705765075216 + 6705765075217.

It is an arithmetic number, because the mean of its divisors is an integer number (6705765075217).

Almost surely, 213411530150433 is an apocalyptic number.

It is an amenable number.

13411530150433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411530150433 is an equidigital number, since it uses as much as digits as its factorization.

13411530150433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 13411530150433 its reverse (33405103511431), we get a palindrome (46816633661864).

The spelling of 13411530150433 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty million, one hundred fifty thousand, four hundred thirty-three".