Base | Representation |
---|---|
bin | 111110011101000101… |
… | …1010111100111111111 |
3 | 110211012001112012221010 |
4 | 1330322023113213333 |
5 | 4144134212420210 |
6 | 141340334010303 |
7 | 12455422400343 |
oct | 1747213274777 |
9 | 424161465833 |
10 | 134120045055 |
11 | 519752a5a47 |
12 | 21bb0646993 |
13 | c855637809 |
14 | 66c474b623 |
15 | 374e8ec920 |
hex | 1f3a2d79ff |
134120045055 has 32 divisors (see below), whose sum is σ = 229338687744. Its totient is φ = 66693802496.
The previous prime is 134120045053. The next prime is 134120045057. The reversal of 134120045055 is 550540021431.
It is an interprime number because it is at equal distance from previous prime (134120045053) and next prime (134120045057).
It is a cyclic number.
It is not a de Polignac number, because 134120045055 - 21 = 134120045053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134120045053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2430477 + ... + 2485046.
It is an arithmetic number, because the mean of its divisors is an integer number (7166833992).
Almost surely, 2134120045055 is an apocalyptic number.
134120045055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
134120045055 is a deficient number, since it is larger than the sum of its proper divisors (95218642689).
134120045055 is a wasteful number, since it uses less digits than its factorization.
134120045055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4915655.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 134120045055 its reverse (550540021431), we get a palindrome (684660066486).
The spelling of 134120045055 in words is "one hundred thirty-four billion, one hundred twenty million, forty-five thousand, fifty-five".
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