Base | Representation |
---|---|
bin | 11000111110110101… |
… | …10011010010011111 |
3 | 1021121201002021120121 |
4 | 30133122303102133 |
5 | 204431434141112 |
6 | 10054510055411 |
7 | 653235205141 |
oct | 143732632237 |
9 | 37551067517 |
10 | 13412021407 |
11 | 5762811214 |
12 | 27237aa567 |
13 | 1359861c55 |
14 | 91337cc91 |
15 | 5376dc407 |
hex | 31f6b349f |
13412021407 has 2 divisors, whose sum is σ = 13412021408. Its totient is φ = 13412021406.
The previous prime is 13412021387. The next prime is 13412021431. The reversal of 13412021407 is 70412021431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13412021407 - 223 = 13403632799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13412021437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706010703 + 6706010704.
It is an arithmetic number, because the mean of its divisors is an integer number (6706010704).
Almost surely, 213412021407 is an apocalyptic number.
13412021407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13412021407 is an equidigital number, since it uses as much as digits as its factorization.
13412021407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 13412021407 its reverse (70412021431), we get a palindrome (83824042838).
The spelling of 13412021407 in words is "thirteen billion, four hundred twelve million, twenty-one thousand, four hundred seven".
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