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13412440211 is a prime number
BaseRepresentation
bin11000111110111000…
…11001100010010011
31021121201212120001212
430133130121202103
5204432041041321
610054523050335
7653241601142
oct143734314223
937551776055
1013412440211
115762a77935
1227239709ab
13135997a771
1491344b759
1553777155b
hex31f719893

13412440211 has 2 divisors, whose sum is σ = 13412440212. Its totient is φ = 13412440210.

The previous prime is 13412440183. The next prime is 13412440213. The reversal of 13412440211 is 11204421431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13412440211 - 230 = 12338698387 is a prime.

Together with 13412440213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13412440213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706220105 + 6706220106.

It is an arithmetic number, because the mean of its divisors is an integer number (6706220106).

Almost surely, 213412440211 is an apocalyptic number.

13412440211 is a deficient number, since it is larger than the sum of its proper divisors (1).

13412440211 is an equidigital number, since it uses as much as digits as its factorization.

13412440211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13412440211 its reverse (11204421431), we get a palindrome (24616861642).

The spelling of 13412440211 in words is "thirteen billion, four hundred twelve million, four hundred forty thousand, two hundred eleven".