Base | Representation |
---|---|
bin | 11000111110111000… |
… | …11001100010010101 |
3 | 1021121201212120001221 |
4 | 30133130121202111 |
5 | 204432041041323 |
6 | 10054523050341 |
7 | 653241601144 |
oct | 143734314225 |
9 | 37551776057 |
10 | 13412440213 |
11 | 5762a77937 |
12 | 27239709b1 |
13 | 135997a773 |
14 | 91344b75b |
15 | 53777155d |
hex | 31f719895 |
13412440213 has 2 divisors, whose sum is σ = 13412440214. Its totient is φ = 13412440212.
The previous prime is 13412440211. The next prime is 13412440291. The reversal of 13412440213 is 31204421431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7244222769 + 6168217444 = 85113^2 + 78538^2 .
It is a cyclic number.
It is not a de Polignac number, because 13412440213 - 21 = 13412440211 is a prime.
Together with 13412440211, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13412440211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706220106 + 6706220107.
It is an arithmetic number, because the mean of its divisors is an integer number (6706220107).
Almost surely, 213412440213 is an apocalyptic number.
It is an amenable number.
13412440213 is a deficient number, since it is larger than the sum of its proper divisors (1).
13412440213 is an equidigital number, since it uses as much as digits as its factorization.
13412440213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13412440213 its reverse (31204421431), we get a palindrome (44616861644).
The spelling of 13412440213 in words is "thirteen billion, four hundred twelve million, four hundred forty thousand, two hundred thirteen".
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