Base | Representation |
---|---|
bin | 111110011101010000… |
… | …0001110010111110101 |
3 | 110211012102210222102021 |
4 | 1330322200032113311 |
5 | 4144142112342211 |
6 | 141341051113141 |
7 | 12455520020443 |
oct | 1747240162765 |
9 | 424172728367 |
10 | 134125512181 |
11 | 5197839a531 |
12 | 21bb24427b1 |
13 | c8568000bb |
14 | 66c5371b93 |
15 | 375012c771 |
hex | 1f3a80e5f5 |
134125512181 has 2 divisors, whose sum is σ = 134125512182. Its totient is φ = 134125512180.
The previous prime is 134125512121. The next prime is 134125512197. The reversal of 134125512181 is 181215521431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 133447743025 + 677769156 = 365305^2 + 26034^2 .
It is a cyclic number.
It is not a de Polignac number, because 134125512181 - 217 = 134125381109 is a prime.
It is a super-2 number, since 2×1341255121812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134125512121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67062756090 + 67062756091.
It is an arithmetic number, because the mean of its divisors is an integer number (67062756091).
Almost surely, 2134125512181 is an apocalyptic number.
It is an amenable number.
134125512181 is a deficient number, since it is larger than the sum of its proper divisors (1).
134125512181 is an equidigital number, since it uses as much as digits as its factorization.
134125512181 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9600, while the sum is 34.
The spelling of 134125512181 in words is "one hundred thirty-four billion, one hundred twenty-five million, five hundred twelve thousand, one hundred eighty-one".
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