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1341300015437 is a prime number
BaseRepresentation
bin10011100001001011101…
…101100000000101001101
311202020010111121121122112
4103201023231200011031
5133433440300443222
62504103522153405
7165622444005554
oct23411355400515
94666114547575
101341300015437
11477929989058
12197b527b2865
139963a5bb9b5
1448cc267cd9b
1524d54b01be2
hex1384bb6014d

1341300015437 has 2 divisors, whose sum is σ = 1341300015438. Its totient is φ = 1341300015436.

The previous prime is 1341300015389. The next prime is 1341300015457. The reversal of 1341300015437 is 7345100031431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 702409933801 + 638890081636 = 838099^2 + 799306^2 .

It is a cyclic number.

It is not a de Polignac number, because 1341300015437 - 234 = 1324120146253 is a prime.

It is a super-2 number, since 2×13413000154372 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1341300015457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670650007718 + 670650007719.

It is an arithmetic number, because the mean of its divisors is an integer number (670650007719).

Almost surely, 21341300015437 is an apocalyptic number.

It is an amenable number.

1341300015437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341300015437 is an equidigital number, since it uses as much as digits as its factorization.

1341300015437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 32.

Adding to 1341300015437 its reverse (7345100031431), we get a palindrome (8686400046868).

The spelling of 1341300015437 in words is "one trillion, three hundred forty-one billion, three hundred million, fifteen thousand, four hundred thirty-seven".