Search a number
-
+
134133214147 is a prime number
BaseRepresentation
bin111110011101011110…
…1100110101111000011
3110211012222022021112021
41330322331212233003
54144201100323042
6141341524142311
712455642336242
oct1747275465703
9424188267467
10134133214147
1151981780099
1221bb4b37997
13c85829898a
1466c63b8959
153750b4e867
hex1f3af66bc3

134133214147 has 2 divisors, whose sum is σ = 134133214148. Its totient is φ = 134133214146.

The previous prime is 134133214121. The next prime is 134133214181. The reversal of 134133214147 is 741412331431.

It is an a-pointer prime, because the next prime (134133214181) can be obtained adding 134133214147 to its sum of digits (34).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134133214147 is a prime.

It is not a weakly prime, because it can be changed into another prime (134133214847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67066607073 + 67066607074.

It is an arithmetic number, because the mean of its divisors is an integer number (67066607074).

Almost surely, 2134133214147 is an apocalyptic number.

134133214147 is a deficient number, since it is larger than the sum of its proper divisors (1).

134133214147 is an equidigital number, since it uses as much as digits as its factorization.

134133214147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24192, while the sum is 34.

Adding to 134133214147 its reverse (741412331431), we get a palindrome (875545545578).

The spelling of 134133214147 in words is "one hundred thirty-four billion, one hundred thirty-three million, two hundred fourteen thousand, one hundred forty-seven".