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134141020124101 is a prime number
BaseRepresentation
bin11110100000000000100011…
…110110101011001111000101
3122120221202102022221112122021
4132200000203312223033011
5120040231302122432401
61153143311154403141
740153240346041624
oct3640004366531705
9576852368845567
10134141020124101
11398179838a1301
12130655182904b1
1359b05a03a7823
14251a6623d56bb
1510794b0ace2a1
hex7a0023dab3c5

134141020124101 has 2 divisors, whose sum is σ = 134141020124102. Its totient is φ = 134141020124100.

The previous prime is 134141020124087. The next prime is 134141020124131. The reversal of 134141020124101 is 101421020141431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87945195968100 + 46195824156001 = 9377910^2 + 6796751^2 .

It is a cyclic number.

It is not a de Polignac number, because 134141020124101 - 239 = 133591264310213 is a prime.

It is a super-2 number, since 2×1341410201241012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134141020124131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67070510062050 + 67070510062051.

It is an arithmetic number, because the mean of its divisors is an integer number (67070510062051).

Almost surely, 2134141020124101 is an apocalyptic number.

It is an amenable number.

134141020124101 is a deficient number, since it is larger than the sum of its proper divisors (1).

134141020124101 is an equidigital number, since it uses as much as digits as its factorization.

134141020124101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 134141020124101 its reverse (101421020141431), we get a palindrome (235562040265532).

The spelling of 134141020124101 in words is "one hundred thirty-four trillion, one hundred forty-one billion, twenty million, one hundred twenty-four thousand, one hundred one".