13414111324330 has 32 divisors (see below), whose sum is σ = 24721065192384. Its totient is φ = 5237861884416.

The previous prime is 13414111324321. The next prime is 13414111324331. The reversal of 13414111324330 is 3342311141431.

13414111324330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13414111324292 and 13414111324301.

It is not an unprimeable number, because it can be changed into a prime (13414111324331) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8177127 + ... + 9679546.

It is an arithmetic number, because the mean of its divisors is an integer number (772533287262).

Almost surely, 2^{13414111324330} is an apocalyptic number.

13414111324330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13414111324330 is a deficient number, since it is larger than the sum of its proper divisors (11306953868054).

13414111324330 is a wasteful number, since it uses less digits than its factorization.

13414111324330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17858470.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 13414111324330 its reverse (3342311141431), we get a palindrome (16756422465761).

The spelling of 13414111324330 in words is "thirteen trillion, four hundred fourteen billion, one hundred eleven million, three hundred twenty-four thousand, three hundred thirty".